Integrand size = 25, antiderivative size = 31 \[ \int \frac {\cos (c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {\log (1+\sin (c+d x))}{a d}+\frac {\sin (c+d x)}{a d} \]
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Time = 0.04 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.120, Rules used = {2912, 12, 45} \[ \int \frac {\cos (c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=\frac {\sin (c+d x)}{a d}-\frac {\log (\sin (c+d x)+1)}{a d} \]
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Rule 12
Rule 45
Rule 2912
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {x}{a (a+x)} \, dx,x,a \sin (c+d x)\right )}{a d} \\ & = \frac {\text {Subst}\left (\int \frac {x}{a+x} \, dx,x,a \sin (c+d x)\right )}{a^2 d} \\ & = \frac {\text {Subst}\left (\int \left (1-\frac {a}{a+x}\right ) \, dx,x,a \sin (c+d x)\right )}{a^2 d} \\ & = -\frac {\log (1+\sin (c+d x))}{a d}+\frac {\sin (c+d x)}{a d} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.16 \[ \int \frac {\cos (c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=\frac {1}{2} \left (-\frac {2 \log (1+\sin (c+d x))}{a d}+\frac {2 \sin (c+d x)}{a d}\right ) \]
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Time = 0.08 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.84
method | result | size |
derivativedivides | \(\frac {\sin \left (d x +c \right )-\ln \left (1+\sin \left (d x +c \right )\right )}{d a}\) | \(26\) |
default | \(\frac {\sin \left (d x +c \right )-\ln \left (1+\sin \left (d x +c \right )\right )}{d a}\) | \(26\) |
parallelrisch | \(\frac {-2 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+\ln \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\sin \left (d x +c \right )}{a d}\) | \(41\) |
risch | \(\frac {i x}{a}-\frac {i {\mathrm e}^{i \left (d x +c \right )}}{2 d a}+\frac {i {\mathrm e}^{-i \left (d x +c \right )}}{2 d a}+\frac {2 i c}{a d}-\frac {2 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )}{a d}\) | \(76\) |
norman | \(\frac {-\frac {2}{a d}-\frac {2 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}-\frac {2 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}-\frac {2 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{2} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}+\frac {\ln \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a d}-\frac {2 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{a d}\) | \(138\) |
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Time = 0.27 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.84 \[ \int \frac {\cos (c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {\log \left (\sin \left (d x + c\right ) + 1\right ) - \sin \left (d x + c\right )}{a d} \]
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Time = 0.28 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.19 \[ \int \frac {\cos (c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=\begin {cases} - \frac {\log {\left (\sin {\left (c + d x \right )} + 1 \right )}}{a d} + \frac {\sin {\left (c + d x \right )}}{a d} & \text {for}\: d \neq 0 \\\frac {x \sin {\left (c \right )} \cos {\left (c \right )}}{a \sin {\left (c \right )} + a} & \text {otherwise} \end {cases} \]
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Time = 0.20 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.97 \[ \int \frac {\cos (c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {\frac {\log \left (\sin \left (d x + c\right ) + 1\right )}{a} - \frac {\sin \left (d x + c\right )}{a}}{d} \]
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Time = 0.29 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.00 \[ \int \frac {\cos (c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {\frac {\log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right )}{a} - \frac {\sin \left (d x + c\right )}{a}}{d} \]
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Time = 0.05 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.84 \[ \int \frac {\cos (c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {\ln \left (\sin \left (c+d\,x\right )+1\right )-\sin \left (c+d\,x\right )}{a\,d} \]
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